Volume
Volume measures the amount of three-dimensional space an object or substance occupies. The standard unit for volume in the International System of Units (SI) is the cubic meter (m³). Typically, the volume of a container refers to its capacity, or the amount of fluid it can hold, rather than the physical space the container itself occupies. Calculating the volume of various shapes is often done using specific mathematical formulas. For complex shapes, they can often be divided into simpler components, and their volumes summed to find the total. Advanced shapes may require integral calculus for precise volume determination, while irregular shapes can be estimated using techniques like the finite element method. Additionally, if a substance’s density is known and uniform, its volume can be derived from its weight. Below are examples of volume calculations for common shapes:
Sphere
A sphere is a three-dimensional version of a circle, defined as the set of points equidistant from a central point. The distance from the center to any point on the sphere is called the radius (r). While a sphere is a hollow surface, a ball includes the space inside it. Both share the same radius, center, and diameter. The volume of a sphere is calculated as:
Volume = (4/3)πr³
Example: Claire wants to fill a spherical water balloon with a radius of 0.15 feet with vinegar. The required volume is:
Volume = (4/3) × π × 0.15³ = 0.141 ft³
Cone
A cone tapers smoothly from a circular base to a single point called the apex. The volume of a cone is given by:
Volume = (1/3)πr²h
where r is the base radius and h is the height.
Example: Bea compares the volumes of a waffle cone (radius 1.5 inches, height 5 inches) and a sugar cone. The waffle cone’s volume is:
Volume = (1/3) × π × 1.5² × 5 = 11.781 in³
Cube
A cube is a three-dimensional shape with six square faces, all meeting at right angles. Its volume is calculated as:
Volume = a³
where a is the length of an edge.
Example: Bob has a cubic suitcase with edges of 2 feet. Its volume is:
Volume = 2³ = 8 ft³
Cylinder
A cylinder consists of two parallel circular bases connected by a curved surface. Its volume is:
Volume = πr²h
where r is the radius and h is the height.
Example: Caelum uses cylindrical barrels (radius 3 feet, height 4 feet) to build a sandcastle. Each barrel’s volume is:
Volume = π × 3² × 4 = 113.097 ft³
Rectangular Tank
A rectangular tank is a box-like shape with six rectangular faces. Its volume is:
Volume = length × width × height
Example: Darby packs a rectangular bag (4 ft × 3 ft × 2 ft) with cake. The volume is:
Volume = 4 × 3 × 2 = 24 ft³
Capsule
A capsule consists of a cylinder with hemispherical ends. Its volume combines the formulas for a cylinder and a sphere:
Volume = πr²h + (4/3)πr³
Example: Joe fills a capsule (radius 1.5 feet, height 3 feet) with melted chocolate. The volume is:
Volume = π × 1.5² × 3 + (4/3) × π × 1.5³ = 35.343 ft³
Spherical Cap
A spherical cap is a portion of a sphere cut off by a plane. Its volume is:
Volume = (1/3)πh²(3R - h)
where R is the sphere’s radius and h is the cap’s height.
Example: Jack cuts a spherical cap (height 0.3 inches) from a golf ball (radius 1.68 inches). The volume is:
Volume = (1/3) × π × 0.3² × (3 × 1.68 - 0.3) = 0.447 in³
Conical Frustum
A conical frustum is the portion of a cone between two parallel planes. Its volume is:
Volume = (1/3)πh(r² + rR + R²)
where r and R are the radii of the two bases.
Example: Bea has a frustum (height 4 inches, radii 0.2 and 1.5 inches) of ice cream. The volume is:
Volume = (1/3) × π × 4 × (0.2² + 0.2 × 1.5 + 1.5²) = 10.849 in³
Ellipsoid
An ellipsoid is a stretched or compressed sphere. Its volume is:
Volume = (4/3)πabc
where a, b, and c are the lengths of the semi-axes.
Example: Xabat fills an ellipsoid bun (axes 1.5, 2, and 5 inches) with meat. The volume is:
Volume = (4/3) × π × 1.5 × 2 × 5 = 62.832 in³
Square Pyramid
A square pyramid has a square base and four triangular faces meeting at an apex. Its volume is:
Volume = (1/3)a²h
where a is the base edge length and h is the height.
Example: Wan builds a mud pyramid (base 5 feet, height 12 feet). The volume is:
Volume = (1/3) × 5² × 12 = 100 ft³
Tube
A tube is a hollow cylinder. Its volume is calculated by subtracting the inner cylinder’s volume from the outer one:
Volume = π(d₁² - d₂²)l / 4
where d₁ and d₂ are the outer and inner diameters, and l is the length.
Example: Beulah builds a pipe (outer diameter 3 feet, inner diameter 2.5 feet, length 10 feet). The volume is:
Volume = π × (3² - 2.5²) × 10 / 4 = 21.6 ft³